Randomly sort a list using LINQ

This is far neater than the loop and temporary list I had in mind. Two lines of code!

Random rnd = new Random();
myList = myList.OrderBy(x => rnd.Next()).ToList();

Or, to take n random elements from a list:

Random rnd = new Random(); 
myList = myList.OrderBy(x => rnd.Next()).Take(n).ToList();